Answer:
A ±sqrt(3/2 x - 6) = y^-1
Step-by-step explanation:
y = 2/3 x^2 +4
To find the inverse exchange x and y and solve for y
Exchange x and y
x = 2/3y^2 +4
Solve for y by first subtracting for from each side
x-4 = 2/3y^2 +4-4
x-4 = 2/3y^2
Multiply each side by 3/2
3/2 (x-4) = 3/2*2/3 y^2
3/2 (x-4) = y^2
Distribute
3/2 x - 6= y^2
Take the square root of each side
±sqrt(3/2 x - 6) = sqrt(y^2)
±sqrt(3/2 x - 6) = y
