Respuesta :

Banabanana
ab + bc + b² + ac = 
(b² + bc)+(ab + ac) = 
b(b+ c)+a(b + с) = 
(b + c)(b + a)
kerriamolden
(ab + b^2) + (bc + ac). 

{So we can get the terms with the same variables together} 

Factoring out the GCF from each term: 

b(a + b) + c(a + b). 

Then, factoring out a + b yields: 

(a + b)(b + c). 

I hope this helps!

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