justme23748
justme23748 justme23748
  • 25-09-2017
  • Mathematics
contestada

solve the system by elimination -2x+2y+3z=0
-2x-y+z=-3
2x+3y+3z=5

Respuesta :

coolstick
coolstick coolstick
  • 25-09-2017
 -2x+2y+3z=0 
-2x-y+z=-3
2x+3y+3z=5

Adding the third equation to the second and first, we get 
5y+6z=5
2y+4z=2

Multiplying the second equation by -6/4 and adding, we get 
   2y=2 and y=1 by dividing both sides by 2. Plugging y=1 into 2y+4z=2, we get 2+4z=2 and by subtracting 2 from both sides we get 4z=0=z. PLugging y=1 and z=0 into 
-2x-y+z=-3, we get -2x-1+0=-3 and by adding 1 to both sides, we get -2x=-2 and by dividing both sides by -2, we get x=1
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jaimelira1900
jaimelira1900 jaimelira1900
  • 16-01-2021

Answer:

2y - 3z=12

-3y - 8z=7

Step-by-step explanation:

on EDG

Answer Link

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