First of all, we need to know what is the vertex means which is the maximum or minimum point of a parabola and the formula will be: x=-b/2a Where b and a from f(x)=ax^2+bx+c So do find which function has a vertex of origin. Let's find the vertex of all the function that we had: f(x)=(x+4)^2 f(x)=(x+4)(x+4) f(x)=x^2+8x+16 x=-b/2a x=-8/2(1) x=-8/2 x=-4 Not the right answer because the vertex needs to be origin which is x=0
f(x)=x(x-4) f(x)=x^2-4x x=-b/2a x=-(-4)/2(2) x=4/4 x=1 Not the right answer
f(x)=(x-4)(x+4) f(x)=x^2-16 x=-0/2(1) x=0 Yay! This is the right answer. As a result, f(x)=(x-4)(x+4) is your final answer. Hope it help!
