Answer:
The answer is the option B
[tex]sin(16\°)=\frac{7}{25}[/tex]
Step-by-step explanation:
we know that
In the right triangle of the figure
[tex]sin(16\°)=\frac{opposite\ side\ to\ the\ angle}{hypotenuse}[/tex]
In this problem we have
[tex]opposite\ side\ to\ the\ angle=7\ units[/tex]
[tex]hypotenuse=25\ units[/tex]
Substitutes the values
[tex]sin(16\°)=\frac{7}{25}[/tex]
