Respuesta :

pkmnmushy
If it is known that at 60 °C and 745 torr UF₆ is present only as a gas then we can make the assumption that:

(n/V) = P/RT = (745 torr)/(62.36 L-torr/mol•K)(337 K) = 0.0354 mol/L 
Therefore the density will be:

Density = (352.02 g/mol)(0.0354 mol/L)/(1000 cm³/L) = 0.0125 g/cm³