I kind of feel that it's an exponential equation
[tex]64^{x-3}=4^{x+15}[/tex]
so remember
if
a^x=a^y, whee a=a then x=y
and
(x^m)^n=x^(mn)
so
[tex]64^{x-3}=4^{x+15}[/tex]
64=4^3
[tex](4^3)^{x-3}=4^{x+15}[/tex]
[tex]4^{3(x-3)}=4^{x+15}[/tex]
3(x-3)=x+15
3x-9=x+15
minus x both sides
2x-9=15
minus 9 both sides
2x=6
divide 2
x=3
if it was just normal thing like 64x-3=4x+15, the answer is 3/10
