Answer:
[tex]v_{y}[/tex] = -32.53 m / s
this velocity is directed downwards
Explanation:
This is a free fall exercise, let's use the expression
[tex]v_{y}^{2}[/tex] = v_{oy}^{2} + 2 g (y -yo)
where we are assuming that there is friction with the air, as the body falls its initial velocity is zero
v_{oy} = √ 2g (y - y₀)
let's calculate
v_{y} = √ (2 9.8 (0-54.0))
[tex]v_{y}[/tex] = -32.53 m / s
this velocity is directed downwards
