noraespi5600 noraespi5600

22-04-2020
Physics

contestada

The half-life of phosphorus-32 is 14.26 days. Calculate its decay constant.

Respuesta :

muhammadtalhabinyous muhammadtalhabinyous

22-04-2020

Answer:

5.62 x 10^-7 sec-1

Explanation:

Converting days to seconds:

14.26 x 24x60x60= 1.27 x 10^6

Half life= 0.693 / Decay constant

so

Decay constant = 0.693/1.27x 10^6

= 5.62 x 10^-7

Answer Link

Otras preguntas

Overall, technology has had a beneficial effect on medical treatment. true or false

How to find vertex of F(x) = (x+1)^2 + 4

How far could an object go in three minutes if it starts at 2 m/s But speeds up to 19 m/s

how many atoms does 5.06 grams of oxogen have

10) Ba + H2O → Ba(OH)2 + H2 How do I balance this ?

Find the size of angle YZXGive your answer to 3 significant figures Scroll down to see the shape

How important was teamwork on the Lewis and Clark expedition

Describe the main differences between economies of cities in developed,emerging and developing countries

Which is a correct first step for solving this equation? - 3x + 2 – 5x - 7 = 4x + 2

What is the simplified expression for 6 (2 (y + x))? 6 y + 12 x 12 y + 12 x 12 y + 8 x 8 y + 8 x