Respuesta :

dalendrk
[tex]11-\left(\dfrac{1}{2}\right)^4\cdot48=11-\dfrac{1}{2^4}\cdot48=11-\dfrac{1}{16}\cdot48=11-\dfrac{48}{16}=11-3=8[/tex]

Answer:

The answer is C

Step-by-step explanation: