Thist1979 Thist1979

25-06-2016
Mathematics

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What is the value of y in the equation 2(3y + 6 + 3) = 196 − 16?

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25-06-2016

2(3y + 6 + 3) = 196 - 16

2 x (3y + 9) = 196 - 16

2 x (3y + 9) = 180

2 x 3y + 2 x 9 = 180

6y + 2 x 9 = 180

6y + 18 = 180

6y = 180 - 18

6y = 162

y = 162/6

y = 27

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