Answer:
m∠ADC=55°
Step-by-step explanation:
step 1
Find the value of x
we know that
m∠CDE+m∠EDF=180° ----> by supplementary angles (form a linear pair)
substitute the given values
[tex](2x+1)\°+(x-7)\°=180\°[/tex]
solve for x
[tex]2x+x=180+6[/tex]
[tex]3x=186[/tex]
[tex]x=62[/tex]
step 2
Find the measure of angle ∠ADC
we know that
m∠ADC=m∠EDF ----> by vertical angles
m∠EDF=(x-7)°
substitute the value of x
m∠EDF=(62-7)°=55°
therefore
m∠ADC=55°
