Answer:
C.
Step-by-step explanation:
Choice A:
[tex](4x^2y)^2=(4x^2y)(4x^2y)=(4 \cdot 4)(x^2 \cdot x^2)(y \cdot y)=(16)(x^{2+2})(y^{1+1})=16x^{4}y^{2}[/tex]
Choice B:
[tex]16x^4y^2[/tex] appears exactly the same as choice A simplified.
Choice C:
[tex]16x^2y^4[/tex] is not the same as A or B since x doesn't have power 4 and y doesn't have power 2.
Choice D:
[tex]4^2x^4y^2=(4 \cdot 4)x^4y^2=16x^4y^2[/tex] is the same as A and B.
So the only odd ball is C.
