Answer:
[tex]\boxed{\text{30 mL}}[/tex]
Explanation:
Step 1. Calculate the moles of NaOH
[tex]n = \text{60.0 kg} \times \dfrac{\text{0.0010 mol}}{\text{1 kg}} = \text{0.0600 mol}[/tex]
Step 2. Calculate the volume of NaOH
[tex]V = \text{0.0600 mol} \times \dfrac{\text{1 L}}{\text{2.0 mol}} = \text{0.030 L} = \text{30 mL}\\\\\text{The lethal volume of NaOH is } \boxed{\textbf{30 mL}}[/tex]
