Answer:
(1, -2)
Step-by-step explanation:
We have the two equations:
y ≤ -x + 3 (1)
y ≤ x^2 - 3x → Factorizing → y ≤ x(x-3) (2)
So the two equations are:
y ≤ x(x-3)
y ≥ (x-3)
Solving the system of equations:
y=x(x-3)
y = (x-3)
Then: x(x-3) = (x-3). Solving for 'x' we have that x=1.
If x=1, then y= -2
The point thay satisfies the inequations is:
(1, -2)
