Answer:
[tex]f^{-1}[/tex](x) = [tex]\frac{x-2}{8}[/tex]
Step-by-step explanation:
let y = f(x) and rearrange making x the subject
y = 8x + 2
8x + 2 = y ( subtract 2 from both sides )
8x = y - 2 ( divide both sides by 8 )
x = [tex]\frac{y-2}{8}[/tex]
change y back into terms of x, hence
[tex]f^{-1}[/tex] (x) = [tex]\frac{x-2}{8}[/tex]
