Consider the expression [tex]5 \times 18[/tex]
Expanding 18 as (10+8),
= [tex]5 \times (10+8)[/tex]
By using distributive property, we get
= [tex]( 5 \times 10) + ( 5 \times 8)[/tex]
= 50 + 40
By adding, we get
= 90
The digit at units place is '0' and the digit at tens place is '9'.
Therefore, there are 9 tens in the final product of [tex]5 \times 18[/tex].
