Respuesta :

gmany

[tex]\text{The domain:}\\D:x\geq0\\\\2\sqrt{x}+20=15+3\sqrt{x}\ \ \ |-20\\\\2\sqrt{x}=-5+3\sqrt{x}\ \ \ \ |-3\sqrt{x}\\\\-\sqrt{x}=-5\ \ \ |\text{change the signs}\\\\\sqrt{x}=5\ \ \ |\text{square both side}\\\\x=25[/tex]


Answer: B. 25

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