We will use the angle bisector theorem here for [tex] \angle GEH [/tex]. ED being the angle bisector.
Thus, from the diagram we will have:
[tex] \frac{HD}{DG} =\frac{EH}{EG} [/tex]
We will now plug in the values given in the diagram.
[tex] \frac{35}{x+4} =\frac{56}{44.8} [/tex]
[tex] x+4=\frac{35\times 44.8}{56} [/tex]
[tex] x+4=28 [/tex]
[tex] x=24 [/tex]
