Answer:
2x-4y-5z +21 =0 is the equation.
Step-by-step explanation:
Given the line can be written as
[tex]\frac{x-5}{-4} =\frac{y-3}{8} =\frac{z}{10}[/tex]
The line has direction ratios (-4, 8, 10)
Since the plane is perpendicular to this line, this line is normal to the plane.
It passes through (2,5,1)
Hence plane will have equation as
-4(x-2)+8(y-5)+10(z-1) =0 Or
-4x+8y+10z +8-40-10 =0
4x-8y-10z +42 =0
Divide by 2
2x-4y-5z +21 =0
