Respuesta :

[tex]\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{9}{ h},\stackrel{-1}{ k})\qquad \qquad radius=\stackrel{7}{ r} \\\\\\\ [x-9]^2+[y-(-1)]^2=7^2\implies (x-9)^2+(y+1)^2=49[/tex]

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