legacycreator10 legacycreator10

21-05-2018
Mathematics

contestada

In the triangle below, what ratio is sec H?

In the triangle below what ratio is sec H class=

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calculista calculista

31-05-2018

we know that
in the right triangle FGH
cos H=adjacent side angle H/hypotenuse
adjacent side angle H=g
hypotenuse=f
so
cos H=g/f
sec H=1/cos H
sec H=1/(g/f)-----> sec H=f/g

the answer is
sec H=f/g

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